Question: If does exist? f(x, y) xy x + y 2
If 
does

exist?
f(x, y) xy x + y 2
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Figure 5 If y 0 then fx 0 0x 0 Therefore fxy 0 If x 0 then f0 y 0y 0 so fxy 0 as as xy 00 al... View full answer
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