We learn in trigonometry that sin x sin( x) Hence f(sin x) f(sin x ) Now let f(x) x sin x Then x sin x ( x) sin( x) or x x Hence 2x and since x is any value we choose, so is What is wrong

Question: We learn in trigonometry that sin x sin( x). Hence f(sin x) = f(sin[ x]). Now let f(x) = x sin x.

We learn in trigonometry that sin x ≡ sin(π − x). Hence f(sin x) = f(sin[π − x]). Now let f(x) = x sin x. Then x sin x = (π − x) sin(π − x) or x = π − x. Hence π = 2x and since x is any value we choose, so is π. What is wrong?

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