Question: Let f(x) = ax(1 - x), where a is a real number and 0 x 1. Recall that the fixed point of a

Let f(x) = ax(1 - x), where a is a real number and 0 ≤ x ≤ 1. Recall that the fixed point of a function is a value of x such that f(x) = x. 

a. Without using a calculator, find the values of a, with 0 < a ≤ 4, such that f has a fixed point. Give the fixed point in terms of a.

b. Consider the polynomial g(x) = f(f(x)). Write g in terms of a and powers of x. What is its degree?

c. Graph g for a = 2, 3, and 4.

d. Find the number and location of the fixed points of g for a = 2, 3, and 4 on the interval 0 ≤ x ≤ 1.

Step by Step Solution

3.48 Rating (164 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

a We are seeking solutions of fx ax1 x x This can be written as ax 2 x1 a 0 or xax 1 a 0 The solutio... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Calculus Early Transcendentals Questions!