Question: Show that cosh -1 (cosh x) = |x| by using the formula cosh -1 t = ln (t + t 2 - 1) and by

Show that cosh-1 (cosh x) = |x| by using the formula cosh-1 t = ln (t + √t2 - 1) and by considering the cases x ≥ 0 and x < 0.

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