Question: Suppose you evaluate dx/x using integration by parts. With u = 1/x and dv = dx, you find that du = -1/x 2 dx,

Suppose you evaluate ∫ dx/x using integration by parts. With u = 1/x and dv = dx, you find that du = -1/x2 dx, v = x, and

/4-()- - /()«-- dx dx. dx = 1 + .2

You conclude that 0 = 1. Explain the problem with the calculation.

/4-()- - /()-- dx dx. dx = 1 + .2

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