Question: A projectile is shot straight up with an initial velocity of 512 ft per second. Its height above the ground after t seconds is given
A projectile is shot straight up with an initial velocity of 512 ft per second. Its height above the ground after t seconds is given by s(t) = 512t - 16t2.
(a) Find the velocity and acceleration after t seconds.
(b) What is the maximum height attained?
(c) When does the projectile hit the ground and with what velocity?
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