Question: A projectile is shot straight up with an initial velocity of 512 ft per second. Its height above the ground after t seconds is given

A projectile is shot straight up with an initial velocity of 512 ft per second. Its height above the ground after t seconds is given by s(t) = 512t - 16t2.

(a) Find the velocity and acceleration after t seconds.
(b) What is the maximum height attained?
(c) When does the projectile hit the ground and with what velocity?

Step by Step Solution

3.38 Rating (154 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

a b The maximum height is attained when The height reaches a ... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Calculus With Applications Questions!