Question: An object moves along a straight line with velocity a. Find the acceleration a(t) of the object at time t. b. When is the object

An object moves along a straight line with velocity


v(t) = (2t + 9)(8 - 1) for 0 t 5


a. Find the acceleration a(t) of the object at time t.


b. When is the object stationary for 0 ≤ t ≤ 5? Find the acceleration at each such time.


c. When is the acceleration zero for 0 ≤ t ≤ 5? Find the velocity at each such time.


d. Use the graphing utility of your calculator to draw the graphs of the velocity v(t) and acceleration a(t) on the same screen.


e. The object is said to be speeding up when v(t) and a(t) have the same sign (both positive or both negative). Use your calculator to determine when (if ever) this occurs for 0 ≤ t ≤ 5.

v(t) = (2t + 9)(8 - 1) for 0 t 5

Step by Step Solution

3.32 Rating (164 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

a b The object is stationary when vt 0 The function 2t 9 2 8 1 ... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Calculus With Applications Questions!