Question: Lucky Larry was faced with solving log(2x + 1) - log(3x - 1) = 0. Larry just dropped the logs and proceeded: (2x + 1)

Lucky Larry was faced with solving

log(2x + 1) - log(3x - 1) = 0.
Larry just dropped the logs and proceeded:
(2x + 1) - (3x - 1) = 0
-x + 2 = 0
x = 2.
Although Lucky Larry is wrong in dropping the logs, his procedure will always give the correct answer to an equation of the form log A - log B = 0, where A and B are any two expressions in x. Prove that this last equation leads to the equation A - B = 0, which is what you get when you drop the logs.

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