Question: a. Given that 3sec + 4 cosec = 2 cosec 2, show that 3sin + 4 cos = 1. b. Express 3sin +
a. Given that 3sec θ + 4 cosec θ = 2 cosec 2θ, show that 3sinθ + 4 cosθ = 1.
b. Express 3sinθ + 4 cosθ in the form Rsin(θ + α) , where R > 0 and 0°< α < 90°.
Give the value of α correct to 2 decimal places.
c. Hence solve the equation 3secθ + 4 cosecθ = 2 cosec 2θ for 0°< θ < 360°.
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a We are given 3sec 4cosec 2cosec 2 We can write cosec 2 as 2cosec cos 3sec 4cosec 22cosec cos Divid... View full answer
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