a. Show that the equation 8sin 2 + 2 cos 2 cos = 6

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a. Show that the equation 8sin2θ + 2 cos2θ − cosθ = 6 can be written in the form 6 cos2θ + cosθ − 2 = 0.
b. Hence, solve the equation 8sin2θ + 2 cos2θ − cosθ = 6 for 0° ≤ θ ≤ 360°.

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