i Solve the equation 2cos 2 3sin, for 0 360 ii The smallest positive solution of the equation 2 cos 2 (n) 3sin(n), where n is a positive integer, is 10 State the value of n and hence find the largest solution of this equation in the interval 0 360

Question: i. Solve the equation 2cos 2 = 3sin, for 0 < < 360. ii. The smallest positive solution of the equation 2 cos

i. Solve the equation 2cos²θ = 3sinθ, for 0° < θ < 360°.
ii. The smallest positive solution of the equation 2 cos²(nθ) = 3sin(nθ), where n is a positive integer, is 10°. State the value of n and hence find the largest solution of this equation in the interval 0° ≤ θ ≤ 360°.

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i To solve the equation 2cos2 3sin we can use the identity cos2 sin2 1 to write it as 21 sin2 3sin E... View full answer

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