Show that for small values of x 2 , (1 2x 2 ) 2 (1 6x 2 ) 2 3 kx 4 , where the value of constant k to be determined ...

We can start by using the binomial expansion to approximate the first term 1 2x22 for small values ...

Show that for small values of x 2 , (1 2x 2 ) 2 (1

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Show that for small values of x², (1 − 2x²)⁻² − (1 + 6x²)^2/3 ≈ kx⁴, where the value of constant k to be determined.

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Cambridge International AS & A Level Mathematics Pure Mathematics 2 & 3 Coursebook

ISBN: 9781108407199

1st Edition

Authors: Sue Pemberton, Julianne Hughes, Julian Gilbey

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Question Posted: Mar 29, 2023 04:16 AM

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Show that for small values of x 2 , (1 2x 2 ) 2 (1

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We can start by using the binomial expansion to approximate the first term 1 2x22 for small values ...View the full answer

Cambridge International AS & A Level Mathematics Pure Mathematics 2 & 3 Coursebook

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