Solve a log 2 x log 2 (x 1) log 2 20 b log 5 (x 2) log x (x 5) log 5 4x c 2 log 3 x log 3 (x 2) 2 d 3 2 log 2 x log 2 (3 10x)

Question: Solve. a. log 2 x + log 2 (x - 1) = log 2 20 b. log 5 (x - 2) + log x (x

Solve.

a. log₂x + log₂ (x - 1) = log₂ 20

b. log₅ (x - 2) + log_x (x - 5) = log₅ 4x

c. 2 log₃ x - log₃ (x - 2) = 2

d. 3 + 2 log₂ x = log₂ (3 − 10x)

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a log2 x log2 x 1 log2 20 The left side of the equation can be made simpler by applying the product rule of logarithms as follows log2xx 1 log220 Now that we have the definition of a logarithm we can ... View full answer

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