Question: Solve. a. |x + 4| < |2x| b. |2x 5| > 3 x c. |3x 2| < 1 3x d. |x

Solve.

a. |x + 4| < |2x| 

b. |2x − 5| > 3 − x 

c. |3x − 2| <  1 − 3x

d. |x − 1| > 2 x − 4 

e. 3|3 − x| >  |2x − 1| 

f. |3x − 5| < 2|2 − x|

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a x 4 2x We can solve this by considering two cases When x 4 is positive we have x 4 2x which gives ... View full answer

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