Question: Solve each equation for 0 < < 180. a. 6sec 3 5sec 2 8 sec + 3 = 0 b.
Solve each equation for 0° < θ < 180°.
a. 6sec3θ − 5sec2 θ − 8 secθ + 3 = 0
b. 2 cot3 + 3cosec2 − 8 cot θ = 0
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a To solve the equation 6sec3 5sec2 8 sec 3 0 for 0 180 we can use a substitution to simplify the equation Let x sec then the equation becomes a cubic ... View full answer
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