Solve each equation for 0 180 a 2 sin2 tan 1 b 3cos 2 cos 2 c 2 cosec 2 2 tan 3sec d 2 tan2 3cot e tan2 4 cot f cot 2 cot 3 ...

a 2 sin2 tan 1 Using the identity sin2 2sincos we can rewrite the equation as 22sincos tan 1 4sincos ...

Solve each equation for 0 < < 180. a. 2 sin2 tan = 1 b. 3cos

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Solve each equation for 0° < θ <180°.

a. 2 sin2θ tanθ = 1

b. 3cos 2θ + cosθ = 2

c. 2 cosec 2θ + 2 tanθ = 3secθ

d. 2 tan2θ = 3cotθ

e. tan2θ = 4 cotθ

f. cot 2θ+ cotθ = 3

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Cambridge International AS & A Level Mathematics Pure Mathematics 2 & 3 Coursebook

ISBN: 9781108407199

1st Edition

Authors: Sue Pemberton, Julianne Hughes, Julian Gilbey

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Question Posted: Mar 14, 2023 07:17 AM

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Solve each equation for 0 < < 180. a. 2 sin2 tan = 1 b. 3cos

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a 2 sin2 tan 1 Using the identity sin2 2sincos we can rewrite the equation as 22sincos tan 1 4sincos ...View the full answer

Cambridge International AS & A Level Mathematics Pure Mathematics 2 & 3 Coursebook

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