The equation of a circle is x 2 + y 2 8x + 4y + 4
Question:
The equation of a circle is x2 + y2 − 8x + 4y + 4 = 0.
a. Find the radius of the circle and the coordinates of its centre.
b. Find the x-coordinates of the points where the circle crosses the x-axis, giving your answers in exact form.
c. Show that the point A(6, 2√3 − 2) lies on the circle.
d. Show that the equation of the tangent to the circle at A is √3x + 3y = 12 √3 − 6.
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Step by Step Answer:
a To find the center and radius of the circle we need to rewrite the equation in standard form x h y ...View the full answer
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Related Book For 
Cambridge International AS And A Level Mathematics Pure Mathematics 1 Coursebook
ISBN: 9781108407144
1st Edition
Authors: Sue Pemberton, Julian Gilbey
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