Triangle ABC has vertices at A(7, 8), B(3, k) and C(8, 5). Given that AB = 2BC,
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Triangle ABC has vertices at A(−7, 8), B(3, k) and C(8, 5). Given that AB = 2BC, find the value of k.
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We can start by finding the lengths of AB and BC using the distance formula AB sqrt3 72 k 82 sqrt100 ...View the full answer
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Related Book For
Cambridge International AS And A Level Mathematics Pure Mathematics 1 Coursebook
ISBN: 9781108407144
1st Edition
Authors: Sue Pemberton, Julian Gilbey
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