Question: 5.29 The horseshoe crab x = width values in Table 3.2 have a mean of 26.3 and standard deviation of 2.1. If the true relationship

5.29 The horseshoe crab x = width values in Table 3.2 have a mean of 26.3 and standard deviation of 2.1. If the true relationship were similar to the fitted equation reported in Section 4.1.3, namely, ˆπ = exp(−12.351 + 0.497x)/[1 +

exp(−12.351 + 0.497x)], how large a sample yields P(type II error) = 0.10 in an α = 0.05-level test of independence? Use the alternative of a positive effect of width on the probability of a satellite.

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