Chromium(VI) forms two different oxyanions, the orange dichromate ion (left(mathrm{Cr}_{2} mathrm{O}_{7}{ }^{2-}ight)) and the yellow chromate ion
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Chromium(VI) forms two different oxyanions, the orange dichromate ion \(\left(\mathrm{Cr}_{2} \mathrm{O}_{7}{ }^{2-}ight)\) and the yellow chromate ion \(\left(\mathrm{CrO}_{4}{ }^{2-}ight)\). The equilibrium reaction between the two ions is
\[\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}(a q)+\mathrm{H}_{2} \mathrm{O}(l) ightleftharpoons 2 \mathrm{CrO}_{4}^{2-}(a q)+2 \mathrm{H}^{+}(a q)\]
The following pictures show what happens when sodium hydroxide is added to a dichromate solution.
Explain what happened.
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