The pre-equilibrium and the steady-state approximations are two different approaches to deriving a rate law from a

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The pre-equilibrium and the steady-state approximations are two different approaches to deriving a rate law from a proposed mechanism. For the following mechanism, determine the rate law

(a) By the pre-equilibrium approximation and

(b) By the steady-state approximation.

(c) Under what conditions do the two methods give the same answer?

(d) What will the rate laws become at high concentrations of Br^–? CH3OH + H ; CH3OH+ + CH3OH + Br (fast equilibrium) CH3Br + HO (slow)

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Chemical Principles The Quest For Insight

ISBN: 9781464183959

7th Edition

Authors: Peter Atkins, Loretta Jones, Leroy Laverman

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Question Posted: Jan 01, 2024 10:38 AM

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The pre-equilibrium and the steady-state approximations are two different approaches to deriving a rate law from a

Question:

CH3OH + H ; CHOH+ + CH3OH + Br (fast equilibrium) CH3Br + HO (slow)

Step by Step Answer:

CH3OH H CH3OH k CH3OH2 Br CH3Br H2O a The rate law will be based upon the second step which is the s...View the full answer

Chemical Principles The Quest For Insight

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