Consider the simple one-step reaction: Since the reaction occurs in a single step, the forward reaction has

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Consider the simple one-step reaction:

A(g) : B(g)

Since the reaction occurs in a single step, the forward reaction has a rate of kfor[A] and the reverse reaction has a rate of krev[B].

What happens to the rate of the forward reaction when we increase the concentration of A? How does this explain the reason behind Le Châtelier’s principle?

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