The osmotic pressure of a solution containing 5.87 mg of an unknown protein per 10.0 mL of
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The osmotic pressure of a solution containing 5.87 mg of an unknown protein per 10.0 mL of solution is 2.45 torr at 25 °C. Find the molar mass of the unknown protein.
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SORT You are told that a solution of an unknown protein contains 5.87 mg of the protein per 10.0 mL of solution. You are also given the osmotic pressure of the solution at a particular temperature and asked to find the molar mass of the unknown protein. STRATEGIZE Step 1: Use the given osmotic pressure and temper- ature to find the molarity of the protein solution. Step 2: Use the molarity calculated in step 1 to find the number of moles of protein in 10 mL of solution. Step 3: Finally, use the number of moles of the protein calculated in step 2 and the given mass of the protein in 10.0 mL of solution to find the molar mass. GIVEN: 5.87 mg protein 10.0 mL solution II = 2.45 torr T = 25 °C FIND: molar mass of protein (g/mol) CONCEPTUAL PLAN П, Т II = MRT mL solution. M Molar mass= 1L 1000 mL L solution mol protein L solution mol protein from first step mass protein moles protein RELATIONSHIPS USED II = MRT (osmotic pressure equation)
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II MRT M II RT 245 terf X 100 mL X 008206 ...View the full answer
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