The reaction was examined at 250C. At equilibrium, [PCl 5 ] =4.2 10 5 mol/L, [PCl
Question:
The reaction
was examined at 250°C. At equilibrium, [PCl5] =4.2 × 10−5 mol/L, [PCl3] = 1.3 × 10−2 mol/L, and [Cl2] = 3.9 × 10−3 mol/L. Calculate Kc for the reaction.
Transcribed Image Text:
PC15 (8) PC13(g) + Cl₂(g)
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PCl5 9 PC13 9 Cl29 The equilibrium constant K for the reaction is given by the express...View the full answer
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Related Book For
Chemistry And Chemical Reactivity
ISBN: 9780357001172
10th Edition
Authors: John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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