The atomic mass of 40 Ca is 39.96259 u. What is the binding energy per nucleon (in

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The atomic mass of ⁴⁰Ca is 39.96259 u. What is the binding energy per nucleon (in MeV) in this atom?

Strategy Calculate the mass defect from the sum of the masses of the particles and from the atomic mass of the atom. Convert the mass defect into binding energy in megaelectron volts and divide by the number of nucleons.

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Chemistry Principles And Practice

ISBN: 9780534420123

3rd Edition

Authors: Daniel L. Reger, Scott R. Goode, David W. Ball

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Question Posted: Jan 13, 2024 07:00 AM

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The atomic mass of 40 Ca is 39.96259 u. What is the binding energy per nucleon (in

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We know that the nucleus contains 20 neutrons and 20 protons plus 20 electrons fr...View the full answer

Chemistry Principles And Practice

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