Question: Whats wrong with this argument? Suppose x and y represent two real numbers, where x > y. The final inequality, y > x, is impossible

What’s wrong with this argument? Suppose x and y represent two real numbers, where x > y. 2 > 1 2(yx) > 1(y-x) 2y - 2x > y - The final inequality, y > x, is impossible because we were initially given x > y.

2 > 1 2(yx) > 1(y-x) 2y - 2x > y - x y - 2x > -x y > x This is a true statement. Multiply both sides by y - x. Use the distributive property. Subtract y from both sides. Add 2x to both sides.

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