Question: A projectile is launched straight up from ground level with an initial velocity of 96 ft per sec. Its height in feet, s, after t

A projectile is launched straight up from ground level with an initial velocity of 96 ft per sec. Its height in feet, s, after t seconds is given by the equation

s = -16t² + 96t.

(a) At what time(s) will it reach a height of 80 ft?

(b) After how many seconds will it return to the ground?

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