Find the equation of the tangent to the curve a) y = x 6x + 3

Find the equation of the tangent to the curve

a) y = x³ − 6x + 3 at the point (2, −1)

b) y = 2x⁴ + 9x³ + x when x = −2

c) y = (x − 7)(x + 4) at the point when x = 1

d) y= x⁴ – 3x³/x at the point (1, −2)

e) y = √x(x² − 1) at the point (1,16)

f) y = ³√x at the point when x = 8.