Prove the Internet checksum computation shown in the text is independent of byte order (host order or network order) except that the bytes in the final checksum should be swapped later to be in the correct order. Specifically, show that the sum of 16-bit words can be computed in either byte order. For example, if the ones’ complement sum (denoted by +’) of 16-bit words is represented as

then the following swapped sum is the same as the original sum above:

[A, B] + [C,D] + ... +' [Y,Z),