Question: Repeat Problem P4-3 for the 2B1Q scheme, but use the following data streams. a. 0000000000000000 b. 1111111111111111 c. 0101010101010101 d. 0011001100110011 Problem 4-3 Draw the

Repeat Problem P4-3 for the 2B1Q scheme, but use the following data streams.
a. 0000000000000000
b. 1111111111111111
c. 0101010101010101
d. 0011001100110011

Problem 4-3

Draw the graph of the NRZ-L scheme using each of the following data streams, assuming that the last signal level has been positive. From the graphs, guess the bandwidth for this scheme using the average number of changes in the signal level. Compare your guess with the corresponding entry in Table 4.1.

Characteristics Category Scheme Bandwidth (average) Costly, no self-synchronization if long Os or 1s, DC No self-synchro

Characteristics Category Scheme Bandwidth (average) Costly, no self-synchronization if long Os or 1s, DC No self-synchronization if long Os or 1s, DC No self-synchronization for long Os, DC Self-synchronization, no DC, high bandwidth No self-synchronization for long Os, DC Unipolar NRZ B = N/2 NRZ-L B = N/2 B = N/2 NRZ-I Polar Biphase B = N Bipolar AMI B = N/2 B = N/4 2B1Q No self-synchronization for long same double bits Multilevel 8B6T B = 3 N/4 Self-synchronization, no DC Self-synchronization, no DC No self-synchronization for long 0Os 4D-PAM5 B= N/8 Multitransition MLT-3 B= N/3

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