Question: To understand why we need to have a minimum frame size T fr = 2 T p in a CDMA/CD network, assume we have
To understand why we need to have a minimum frame size Tfr = 2 × Tp in a CDMA/CD network, assume we have a bus network with only two stations, A and B, in which Tfr = 40 μs and Tp = 25 μs. Station A starts sending a frame at time t = 0.0 μs and station B starts sending a frame at t = 23.0 μs. Answer the following questions:
a. Do frames collide?
b. If the answer to part a is yes, does station A detect collision?
c. If the answer to part a is yes, does station B detect collision?
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The first bit of each frame needs at least 25 s to reach its destination ... View full answer
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