Question: The system having the Bode magnitude plot as shown below has the transfer function (a) (frac{60(s+0.01)(s+0.1)}{s^{2}(s+0.05)^{2}}) (b) (frac{100(1+10 s)}{s(1+20 s)}) (c) (frac{3(s+0.05 s)}{s(s+0.1)(s+1)}) (d) (frac{5(s+0.1)}{s(s+0.05)})
The system having the Bode magnitude plot as shown below has the transfer function
(a) \(\frac{60(s+0.01)(s+0.1)}{s^{2}(s+0.05)^{2}}\)
(b) \(\frac{100(1+10 s)}{s(1+20 s)}\)
(c) \(\frac{3(s+0.05 s)}{s(s+0.1)(s+1)}\)
(d) \(\frac{5(s+0.1)}{s(s+0.05)}\)

dB 0 - 6 dB/oct 12 dB/oct .01 .05 0.1 - 6 dB/oct 1.0 w (log scale) 10
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Bode plots consist of two graphs one for magnitude in dB and one for phase in degrees both plotted against frequency on a logarithmic scale From the B... View full answer
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