Question: In the Diffie-Hellman protocol, each participant selects a secret number (x) and sends the other participant (alpha^{x} bmod q) for some public number (alpha). What

In the Diffie-Hellman protocol, each participant selects a secret number $x$ and sends the other participant $\alpha^{x} \bmod q$ for some public number $\alpha$. What would happen if the participants sent each other $x^{\alpha}$ for some public number $\alpha$ instead? Give at least one method Alice and Bob could use to agree on a key. Can Eve break your system without finding the secret numbers? Can Eve find the secret numbers?

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