Question: Prove the following: a. ([(a bmod n)-(b bmod n)] bmod n=(a-b) bmod n) b. (quad[(a bmod n) times(b bmod n)] bmod n=(a times b) bmod

Prove the following:

a. \([(a \bmod n)-(b \bmod n)] \bmod n=(a-b) \bmod n\)

b. \(\quad[(a \bmod n) \times(b \bmod n)] \bmod n=(a \times b) \bmod n\)

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