Question: Simplify the following expressions using Boolean algebra. (a) x = ABC + AC (b) y (Q + R) (Q + R) (c) w = ABC

Simplify the following expressions using Boolean algebra.

(a) x = ABC + AC (b) y (Q + R) (Q + R) (c) w = ABC + ABC + A (d) q = RST(R + S + T) = (e) x = ABC + ABC + ABC

(a) x = ABC + AC (b) y (Q + R) (Q + R) (c) w = ABC + ABC + A (d) q = RST(R + S + T) = (e) x = ABC + ABC + ABC + ABC + ABC (f) 2 (B+C)(B+C) + A + B + C (g) y = (C+D) + ACD + ABC + ABCD + ACD (h) x = AB(CD) + ABD + BCD

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a x ABC AC We can use the distributive law AB C AB AC x ABC AC ABC C AB 1 A1 A So the simplified exp... View full answer

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