Question: Show that the first least squares assumption, (Eleft(u_{i} mid X_{i} ight)=0), implies that (Eleft(Y_{i} mid X_{i} ight)=beta_{0}+beta_{1} X_{i}).

Show that the first least squares assumption, $E\left(u_{i} \mid X_{i}\right)=0$, implies that $E\left(Y_{i} \mid X_{i}\right)=\beta_{0}+\beta_{1} X_{i}$.

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