a. Comment on the change in capacitance level with an increase in the reverse-bias potential for the diode of Fig. 1.37.

b. What is the level of C (0)?

c. Using V_K 0.7 V, find the level of n in Eq. 1.9.

Fig. 1.37 .

Eq. 1.9.

Transcribed Image Text:

FORWARD VOLTAGE VERSUS REVERSE VOLTAGE VERSUS POWER DERATING CURVE FORWARD CURRENT REVERSE CURRENT Room temperature 1000 IA= 25°C At V=1V. L250 mA 400 100 0.5 0.2 300 10 Boiling water AL V =0.7 V. 30 mA At Vincreases, increases 200 1.0 005 100 0.10 0.02 0.01 0.2 0,4 0.01 O 25 50 75 100 125 150 175 200 0.6 0.8 1.2 25 50 75 100 125 VR - Reverse voltage - volts T- Ambient temperature - C (a) V - Forward voltage - volts (b) (c) REVERSE CURRENT VERSUS TEMPERATURE CAPACITANCE VERSUS REVERSE VOLTAGE DYNAMIC IMPEDANCE VERSUS FORWARD CURRENT SK VR= 125 V 100 6.0 IK 5.0 T=1 kHz 10 Min 4.0 100 Typ I mA, R, 50n 3.0 1,0 10 As T. 2.0 0.1 1.0 0,1 0.01 25 50 75 100 125 150 -16 -12 -8.0 -4.0 1.0 10 100 IK 1OK VR - Reverse voltage – volts (e) T- Ambient lemperature - "C Rp- Dynamic impedance - 2 FIG. 1.37 I8-Reverse current - nA Pp- Power dissipation - mW I- Forward current - mA ly- Forward current - mA R-Reverse current -nA