Question: 16. Conditional probabilities again. The answer is 1 4 (2e1 + e2 + e4). 18. Sn i=1 Ai S i =1 Ai as n

16. Conditional probabilities again. The answer is 1 4 (2e−1 + e−2 + e−4).

18.

Sn i=1 Ai →

S

∞i

=1 Ai as n →∞.

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