Question: [20] Show that there is no computable function f such that f(x) = 1 if x(x) is defined, and f(x) = 0 otherwise. Comments. This

[20] Show that there is no computable function f such that f(x) = 1 if φx(x) is defined, and f(x) = 0 otherwise.

Comments. This fact is known as the computable unsolvability of the halting problem.

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