Question: A particle moves along the curve y = x - (x 2 /400), where x and y are in ft. If the velocity component in

A particle moves along the curve y = x - (x2/400), where x and y are in ft. If the velocity component in the x direction is vx = 2 ft/s and remains constant, determine the magnitudes of the velocity and acceleration when x = 20 ft.

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Velocity Taking the first derivative of the path y x x 2 400 we have Howeve... View full answer

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