Question: At the instant r = 1.5 m, the 5-kg disk is given a speed of v = 5 m/s, perpendicular to the elastic cord. Determine

At the instant r = 1.5 m, the 5-kg disk is given a speed of v = 5 m/s, perpendicular to the elastic cord. Determine the speed of the disk and the rate of shortening of the elastic cord at the instant r = 1.2 m. The disk slides on the smooth horizontal plane. Neglect its size. The cord has an unstretched length of 0.5 m.k = 200 N/m B v = 5 m/s

k = 200 N/m B v = 5 m/s

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Conservation of Energy The intial and final stretch of the elastic cord is s 1 15 05 ... View full answer

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