Question: The 30-kg rod is released from rest when = 0. Determine the angular velocity of the rod when = 90. The spring is

The 30-kg rod is released from rest when θ = 0°.
Determine the angular velocity of the rod when θ = 90°.
The spring is unstretched when θ = 0°. 1.5 m -2 m- wwwwwwww k = 80 N/m

1.5 m -2 m- wwwwwwww k = 80 N/m

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The potential energy of the rod can be expressed as PE 12 k x2 where k is the spring constant and x ... View full answer

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