Question: The 50-lb block rests on the rough surface for which the coeffi cient of kinetic friction is k = 0.2. A force F =
The 50-lb block rests on the rough surface for which the coeffi cient of kinetic friction is μk = 0.2. A force F = (40 + s2) lb, where s is in ft, acts on the block in the direction shown. If the spring is originally unstretched (s = 0) and the block is at rest, determine the power developed by the force the instant the block has moved s = 1.5 ft.
F 30% k = 20 lb/ft wwwww
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1 F 0 T 2U12 T 15 40 0 v2 052936 225 211125 NB 40 s ... View full answer
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