An oxygen molecule is in its vibrational and rotational ground states. It absorbs a photon of energy
Question:
An oxygen molecule is in its vibrational and rotational ground states. It absorbs a photon of energy 0.19653 eV and jumps to the n = 1, l = 1 state. It then drops to n = 0, l = 2, emitting a 0.19546-eV photon. Find
(a) the classical vibration frequency
(b) the rotational inertia of the molecule.
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
a The classical vibration frequency can be determined using ...View the full answer
Answered By
Shahid Akbar
In my point of view, Education can't be finished when it's shared even it will increase in quantity. I like to share my knowledge to everyone who has the interest to improve his skills.
0 Reviews
10+ Question Solved
Related Book For 
Question Posted:
