A curve is such that dy/dx = kx 5 where k is a constant. The gradient
Question:
A curve is such that dy/dx = kx – 5 where k is a constant.
The gradient of the normal to the curve at the point (2, -1) is – 1/3. Find the equation of the curve.
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Since the gradient of the normal to the curve at the point 2 1 is 13 the slope of ...View the full answer
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Related Book For 
Cambridge IGCSE And O Level Additional Mathematics Coursebook
ISBN: 9781108411660
2nd Edition
Authors: Sue Pemberton
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