Variables x and y are such that y = (x -3) ln(2x 2 + 1). i. Find

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Variables x and y are such that y = (x -3) ln(2x² + 1).

i. Find the value of dy/dx when x = 2.

ii. Hence find the approximate change in y when x changes from 2 to 2.03.

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Cambridge IGCSE And O Level Additional Mathematics Coursebook

ISBN: 9781108411660

2nd Edition

Authors: Sue Pemberton

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Question Posted: Sep 02, 2021 12:50 AM

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Variables x and y are such that y = (x -3) ln(2x 2 + 1). i. Find

Question:

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To find the derivative of y with respect to x we can use the chain rule dydx x 3 2x 2 ln2x2 ...View the full answer

Cambridge IGCSE And O Level Additional Mathematics Coursebook

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