Given that x(t) = c 1 cos t + c 2 sin t is the general solution of x'' = 2 x = 0

Given that x(t) =­ c₁ cos ωt + c₂ sin ωt is the general solution of x'' = ω²x =­ 0 on the interval (‑∞,∞), show that a solution satisfying the initial conditions x(0) ­= x₀, x'(0) =­ x₁ is given by

x(t) = x₀ cos ωt + x₁/ω sin ωt.