Problems 23 through 25 deal with the case = 1, so that the system in (6)

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Problems 23 through 25 deal with the case ∈ = 1, so that the system in (6) takes the form

and these problems imply that the three critical points (0,0), (7,0), and (5,2) of the system in (9) are as shown in Fig. 9.3.18 -with saddle points at the origin and on the positive x-axis and with a spiral sink at (5,2). In each problem use a graphing calculator or computer system to construct a phase plane portrait for the linearization at the indicated critical point. Do your local portraits look consistent with Fig. 9.3.18?

Show that the coefficient matrix of the linearization x' = 7x, y' = -5y of (9) at (0,0) has the positive eigenvalue λ1 = 7 and the negative eigenvalue λ2 = -5. Hence (0, 0) is a saddle point for the system in (9).

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Differential Equations And Linear Algebra

ISBN: 9780134497181

4th Edition

Authors: C. Edwards, David Penney, David Calvis

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