Question: The graph of a solution of a second-order initial-value problem d 2 y/dx 2 = f (x, y, y'), y(2) = y 0 , y'(2)
The graph of a solution of a second-order initial-value problem d2y/dx2=Â f (x, y, y'), y(2) =Â y0, y'(2) =Â y1, is given in the following figure. Use the graph to estimate the values of y0and y1.

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