Show that when there is no heat flow (q = 0), no joule heating (J E
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Show that when there is no heat flow (q = 0), no joule heating (J′ · E′ = 0), and when the pressure tensor is isotropic given by P = p1, the energy equation (4.14) reduces to the following adiabatic equation:
Equation 4.14
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To show that the energy equation 414 reduces to the adiabatic equation 53 PPm constant under the given conditions q 0 J E 0 and P p1 we need to simplify the terms in equation 414 using the provided co...View the full answer
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